NUMBERS — Indices and Logarithms

Level: About age 14 (Kenyan secondary). Clear, simple notes with examples and practice questions.

1. Indices (Powers)

Indices (also called powers or exponents) show how many times a number (the base) is multiplied by itself.

Notation

If a is a number and n is a positive whole number, then an means a × a × ... × a (n times). Example: 32 = 3 × 3 = 9, and 53 = 5 × 5 × 5 = 125.

Laws of Indices (simple rules)

  • Product rule: am × an = am+n
  • Quotient rule: am ÷ an = am−n (a ≠ 0)
  • Power of a power: (am)n = am·n
  • Zero exponent: a0 = 1 (for a ≠ 0)
  • Negative exponent: a−n = 1 / an
  • Fractional exponent: a1/2 = √a, and am/n = (√[n]{a})m

Worked Examples — Indices

1) Simplify 23 × 24.   Using product rule: 23+4 = 27 = 128.

2) Simplify 54 ÷ 52.   Using quotient rule: 54−2 = 52 = 25.

3) Simplify (32)3.   (32)3 = 32×3 = 36 = 729.

4) Evaluate 40 and 2−3.   40 = 1; 2−3 = 1 / 23 = 1/8.

5) Write √9 as an index.   √9 = 91/2 = 3.

Quick tips

  • When multiplying same base, add exponents. When dividing, subtract exponents.
  • Negative exponent means reciprocal. Zero exponent gives 1.
  • Fractional exponents connect with roots (e.g., a1/3 is cube root of a).

2. Logarithms

Logarithms are the inverse of indices. They answer the question: "To what power must the base be raised to get a number?"

Definition

If by = x (with b>0, b≠1), then logb(x) = y.

Example: Since 102 = 100, we write log10(100) = 2. This is often written simply as log(100) = 2 (meaning base 10).

Laws of Logarithms

  • Product rule: logb(MN) = logb(M) + logb(N)
  • Quotient rule: logb(M / N) = logb(M) − logb(N)
  • Power rule: logb(Mk) = k · logb(M)
  • Change of base: loga(x) = logc(x) ÷ logc(a) (useful when using a calculator)

Worked Examples — Logarithms

1) Evaluate log10(1000).   Since 103 = 1000, log(1000) = 3.

2) Use the product rule: calculate log10(200) if log(2)=0.3010 and log(100)=2.   log(200) = log(2×100) = log(2) + log(100) = 0.3010 + 2 = 2.3010.

3) Use power rule: log10(10000) = log10(104) = 4·log10(10) = 4·1 = 4.

4) Change of base: find log2(8).   Since 23 = 8, log2(8) = 3. (Or use change of base if needed.)

Connection between indices and logs

Indices: by = x.   Logs: logb(x) = y. They are the same information written differently.

Quick Visual Summary

Think: indices = "multiply many times", logs = "how many times?"

24 = 16   ↔   log2(16) = 4

102 = 100   ↔   log10(100) = 2

Practice Questions

  1. Simplify: 32 × 33.
  2. Write as a single power: (23)2.
  3. Evaluate: 50 and 10−1.
  4. Simplify using indices: 75 ÷ 72.
  5. Write √16 as an index.
  6. Find log10(1000).
  7. Use log rules: If log(2)=0.3010 and log(5)=0.6990, find log(10).
  8. Find log2(32).

Try answering without a calculator for practice.

Answers

  1. 32 × 33 = 35 = 243.
  2. (23)2 = 23×2 = 26 = 64.
  3. 50 = 1.   10−1 = 1/10 = 0.1.
  4. 75 ÷ 72 = 73 = 343.
  5. √16 = 161/2 = 4.
  6. log10(1000) = 3 because 103 = 1000.
  7. log(10) = log(2×5) = log(2) + log(5) = 0.3010 + 0.6990 = 1. (So log10(10) = 1.)
  8. log2(32) = 5 because 25 = 32.

Final Tips

  • Practice converting between roots and fractional indices: √a = a1/2.
  • Use index laws step by step — show exponents clearly when simplifying.
  • Remember logs are just another way to record powers. If unsure, rewrite as by = x to find y.
  • On calculators, log usually means log base 10. Use change-of-base for other bases.

Good work — practise a few examples every day to get confident with indices and logarithms!


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