GRADE 9 Mathematics NUMBERS – INDICES AND LOGARITHMS Notes
NUMBERS — Indices and Logarithms
Level: About age 14 (Kenyan secondary). Clear, simple notes with examples and practice questions.
1. Indices (Powers)
Indices (also called powers or exponents) show how many times a number (the base) is multiplied by itself.
Notation
If a is a number and n is a positive whole number, then an means a × a × ... × a (n times). Example: 32 = 3 × 3 = 9, and 53 = 5 × 5 × 5 = 125.
Laws of Indices (simple rules)
- Product rule: am × an = am+n
- Quotient rule: am ÷ an = am−n (a ≠ 0)
- Power of a power: (am)n = am·n
- Zero exponent: a0 = 1 (for a ≠ 0)
- Negative exponent: a−n = 1 / an
- Fractional exponent: a1/2 = √a, and am/n = (√[n]{a})m
Worked Examples — Indices
1) Simplify 23 × 24. Using product rule: 23+4 = 27 = 128.
2) Simplify 54 ÷ 52. Using quotient rule: 54−2 = 52 = 25.
3) Simplify (32)3. (32)3 = 32×3 = 36 = 729.
4) Evaluate 40 and 2−3. 40 = 1; 2−3 = 1 / 23 = 1/8.
5) Write √9 as an index. √9 = 91/2 = 3.
Quick tips
- When multiplying same base, add exponents. When dividing, subtract exponents.
- Negative exponent means reciprocal. Zero exponent gives 1.
- Fractional exponents connect with roots (e.g., a1/3 is cube root of a).
2. Logarithms
Logarithms are the inverse of indices. They answer the question: "To what power must the base be raised to get a number?"
Definition
If by = x (with b>0, b≠1), then logb(x) = y.
Example: Since 102 = 100, we write log10(100) = 2. This is often written simply as log(100) = 2 (meaning base 10).
Laws of Logarithms
- Product rule: logb(MN) = logb(M) + logb(N)
- Quotient rule: logb(M / N) = logb(M) − logb(N)
- Power rule: logb(Mk) = k · logb(M)
- Change of base: loga(x) = logc(x) ÷ logc(a) (useful when using a calculator)
Worked Examples — Logarithms
1) Evaluate log10(1000). Since 103 = 1000, log(1000) = 3.
2) Use the product rule: calculate log10(200) if log(2)=0.3010 and log(100)=2. log(200) = log(2×100) = log(2) + log(100) = 0.3010 + 2 = 2.3010.
3) Use power rule: log10(10000) = log10(104) = 4·log10(10) = 4·1 = 4.
4) Change of base: find log2(8). Since 23 = 8, log2(8) = 3. (Or use change of base if needed.)
Connection between indices and logs
Indices: by = x. Logs: logb(x) = y. They are the same information written differently.
Quick Visual Summary
Think: indices = "multiply many times", logs = "how many times?"
24 = 16 ↔ log2(16) = 4
102 = 100 ↔ log10(100) = 2
Practice Questions
- Simplify: 32 × 33.
- Write as a single power: (23)2.
- Evaluate: 50 and 10−1.
- Simplify using indices: 75 ÷ 72.
- Write √16 as an index.
- Find log10(1000).
- Use log rules: If log(2)=0.3010 and log(5)=0.6990, find log(10).
- Find log2(32).
Try answering without a calculator for practice.
Answers
- 32 × 33 = 35 = 243.
- (23)2 = 23×2 = 26 = 64.
- 50 = 1. 10−1 = 1/10 = 0.1.
- 75 ÷ 72 = 73 = 343.
- √16 = 161/2 = 4.
- log10(1000) = 3 because 103 = 1000.
- log(10) = log(2×5) = log(2) + log(5) = 0.3010 + 0.6990 = 1. (So log10(10) = 1.)
- log2(32) = 5 because 25 = 32.
Final Tips
- Practice converting between roots and fractional indices: √a = a1/2.
- Use index laws step by step — show exponents clearly when simplifying.
- Remember logs are just another way to record powers. If unsure, rewrite as by = x to find y.
- On calculators, log usually means log base 10. Use change-of-base for other bases.
Good work — practise a few examples every day to get confident with indices and logarithms!