Grade 7 Mathematics ALGEBRA – Linear equations Notes
Mathematics — ALGEBRA
Subtopic: Linear equations (Age: 12, Kenya)
Learning objectives
- Understand what a linear equation is.
- Solve simple one-step and two-step linear equations in one variable.
- Use the balance (transposition) method and check answers.
- Solve simple word problems that lead to a linear equation.
Key terms
- Variable — a letter that represents an unknown number (example: x).
- Coefficient — number multiplied by the variable (in 3x, 3 is the coefficient).
- Constant — a number on its own (example: 5 in x + 5 = 12).
- Linear equation — an equation where the highest power of the variable is 1 (example: ax + b = c).
What is a linear equation?
A linear equation in one variable looks like ax + b = c. Example: 2x + 3 = 11. The goal is to find the value of x that makes the statement true.
Method: The balance (transposition) idea
Think of an equation as a scale that must stay balanced. Whatever you do to one side, do the same to the other.
Left: x + 3
=
Right: 7
To find x, subtract 3 from both sides (keep the balance):
x + 3 = 7 ⇒ x + 3 − 3 = 7 − 3 ⇒ x = 4
Worked examples
-
One-step equation: x + 5 = 12.
Subtract 5 from both sides: x = 12 − 5 = 7. Check: 7 + 5 = 12 ✓
-
Two-step equation: 3x − 4 = 11.
Add 4 to both sides: 3x = 15. Divide both sides by 3: x = 15 ÷ 3 = 5. Check: 3×5 − 4 = 15 − 4 = 11 ✓
-
Variable on both sides: 2x + 3 = x + 8.
Subtract x from both sides: x + 3 = 8. Then subtract 3: x = 5. Check: 2×5 + 3 = 10 + 3 = 13 and x + 8 = 5 + 8 = 13 ✓
-
Fraction: (1/2)x + 3 = 7.
Subtract 3: (1/2)x = 4. Multiply both sides by 2: x = 8. Check: (1/2)×8 + 3 = 4 + 3 = 7 ✓
Word problem (Kenyan context)
Musa buys some exercise books. Each book costs KSh 20. He pays KSh 140. How many books did he buy?
Let x = number of books. Then 20x = 140.
Divide both sides by 20: x = 140 ÷ 20 = 7 books. Check: 7×20 = 140 ✓
Quick tips
- Always perform the same operation on both sides.
- Do addition/subtraction first (to move constants), then multiply/divide to isolate the variable.
- Check your answer by substituting back into the original equation.
- Keep equations tidy: collect like terms before dividing.
Practice exercises
- x + 6 = 14
- 5x = 35
- 4x − 7 = 13
- 2x + 9 = x + 17
- (1/3)x + 5 = 9
- Amina had some coins. She found 8 more coins and now has 21. How many did she have? (Let x = original coins)
- 7x − 2 = 20
- 3(x + 2) = 18
Answers
- x = 8
- x = 7
- 4x − 7 = 13 → 4x = 20 → x = 5
- 2x + 9 = x + 17 → x = 8
- (1/3)x + 5 = 9 → (1/3)x = 4 → x = 12
- x + 8 = 21 → x = 13 coins
- 7x − 2 = 20 → 7x = 22 → x = 22/7 (not an integer)
- 3(x + 2) = 18 → x + 2 = 6 → x = 4
Note: In question 7 the solution is x = 22/7 (you may leave as fraction or decimal ≈ 3.1429).
Extra note
Linear equations in one variable give single number answers (like x = 5). If you learn linear equations in two variables (for example y = 2x + 1) you will see they make straight lines on a graph — this is the next step in algebra.