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Subtopic: Geometry

Context: Kenyan classroom — Target age: age_replace. These notes cover the core ideas, easy examples and practice suitable for learners following Kenyan primary/secondary progression for this age group.

Specific learning outcomes

  • Identify and name basic 2D shapes: triangle, square, rectangle, parallelogram, rhombus, trapezium, circle.
  • Classify triangles by sides and angles; know angle-sum property (triangle = 180°).
  • Understand and measure angles using degrees; identify right, acute, obtuse angles.
  • Calculate perimeter and area of rectangles, squares and right triangles; use formulas with metres and centimetres.
  • Find circumference and area of a circle using π (use π ≈ 3.14 or 22/7 where appropriate).
  • Apply geometry to simple Kenyan contexts (e.g., classroom floor area, small farm plot, blackboard measurements).

Key definitions and formulas

  • Perimeter (P): total distance round a 2D shape. Add all side lengths. Example: rectangle P = 2(l + w).
  • Area (A): amount of flat space inside a shape.
    • Rectangle: A = length × width (A = l × w).
    • Square: A = side².
    • Right triangle: A = 1/2 × base × height.
    • Circle: A = πr², circumference C = 2πr (r = radius).
  • Triangle angle-sum: internal angles add to 180°.
  • Quadrilateral angle-sum: internal angles add to 360°.

Types of triangles

  • By sides: equilateral (all sides equal), isosceles (two equal sides), scalene (no equal sides).
  • By angles: acute (all angles < 90°), right (one 90°), obtuse (one > 90°).

Simple visual aids

b c a (base)
Triangle (sides labelled)
r
Circle (r = radius)

Worked examples

Example 1 — Classroom floor area

A school classroom is a rectangle 6 m long and 5 m wide. Find the floor area and perimeter.

Area = l × w = 6 × 5 = 30 m².
Perimeter = 2(l + w) = 2(6 + 5) = 2 × 11 = 22 m.

Example 2 — Right triangle area

A triangular maize plot has base 8 m and height 5 m (right triangle). Area = 1/2 × base × height = 0.5 × 8 × 5 = 20 m².

Example 3 — Circle (water tank lid)

A circular tank lid has radius 0.7 m. Use π ≈ 3.14.

Area = πr² = 3.14 × 0.7² = 3.14 × 0.49 ≈ 1.54 m².
Circumference = 2πr = 2 × 3.14 × 0.7 ≈ 4.40 m.

Short strategies and tips

  • Draw and label diagrams before calculating. Mark known lengths and angles.
  • Always keep units (m, cm, mm) consistent. Convert where necessary (100 cm = 1 m).
  • For π use 3.14 in most tests; use 22/7 for rough fraction calculation when it simplifies fractions.
  • Check if a triangle is right using Pythagoras: a² + b² = c² (hypotenuse c).

Practice questions

  1. A rectangle has length 9 m and width 4 m. Find its area and perimeter.
  2. A triangle has sides 5 cm, 12 cm and 13 cm. Show it is a right triangle and find its area.
  3. Find the circumference and area of a circle of diameter 14 cm. (Use π = 22/7)
  4. A rhombus has diagonals 10 m and 8 m. Area = (d1 × d2) / 2. Calculate the area.
  5. In a triangle, two angles are 50° and 60°. Find the third angle and state the type by angles.
  6. A classroom blackboard is 1.2 m high and 2.4 m wide. What area of wall does it cover in m²?

Answers (check after trying)

  1. Area = 9 × 4 = 36 m²; Perimeter = 2(9 + 4) = 26 m.
  2. 5² + 12² = 25 + 144 = 169 = 13² so right triangle. Area = 1/2 × 5 × 12 = 30 cm².
  3. Radius = 7 cm. Circumference = 2πr = 2 × (22/7) × 7 = 44 cm. Area = πr² = (22/7) × 7 × 7 = 154 cm².
  4. Area = (10 × 8) / 2 = 40 m².
  5. Third angle = 180 − (50 + 60) = 70°. Type: acute triangle (all angles < 90°).
  6. Area = 1.2 × 2.4 = 2.88 m².

Further study suggestions: practise drawing accurate shapes with ruler and protractor, try measuring items at home (tiles, door, window) and calculate area and perimeter to link geometry to everyday life in Kenya.

📝 Practice Quiz

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